学生成绩处理做一半求助
录入一个班的学生的学号，平时成绩，期末成绩，按照平时成绩×0.3+期末成绩*0.7=总评成绩，计算总评成绩，并统计出各个分数段的人数，并对成绩进行排名type chengji
integer::xuehao
real::pingshichengji
real::qimochengji
real::zongpingchengji
end type
type(chengji) xueshengchengji(n)
print*,"请输入学生人数"
read*,n
print*,"请输入"n"名学生的学号、平时成绩、期末成绩"
print*,"数据之间用空格间隔、学号为长度为12的字符串、用引号括住"
do i=1,n
read*,number(i),pingshichengji(i),qimochengji(i)
zongpingchengji(i)=0.3*pingshichengji(i)+0.7*qimochengji(i)
print*,zongpingchengji(i)
dimension m(11),s(n)!将成绩分为11个分数段0-9、10-19以此类推，一直到100
data m/11 *0/
read(*,*)(s(i),i=1,n)
do i=1,n
if(s(i))<=100.and.s(i)>=0)then
k=s(i)/10+1
m(k)=m(k)+1
end if
end do
write(*,*)m非专业所需，所以学的很浅，后悔了，求助各位大神！急！
FORTRAN 95 program main
implicit none
type chengji
integer::s_id
real::pscj
real::qmcj
real::zcj
end type
integer :: i
type(chengji),allocatable :: student(:)
write(*,*) "请输入学生人数"
read(*,*) n
allocate( student(n) )
write(*,*) "请输入",n,"名学生的学号、平时成绩、期末成绩"
do i =1,n
read(*,*) student(i)%sid,student(i)%pscj,student(i)%qmcj
end do
do i =1,n
student(i)%zcj = 0.3*student(i)%pscj+0.7*student(i)%qmcj
end do
! 然后，排序，统计
end
楼上说的很好！ Jackdaw 发表于 2018-5-31 18:35
program main
implicit none
type chengji
大哥，不会排序啊 这是我们以前的作业，供你参考
Module StudMod
Implicit None
Integer , Parameter :: INUMBER_OF_COURSE = 6
Type T_Stud
Integer :: iStuNumber !//学号
Real :: rScore( INUMBER_OF_COURSE ) !//6门成绩
Real :: rScoreAll , rScoreAvg !//总分和平均分
End Type T_Stud
Contains
Subroutine GetStudInfo( cFilename , stStudArray )
Character( Len = * ) ,Intent( IN ) :: cFilename
Type( T_Stud ) , Intent( OUT ) :: stStudArray( : )
Integer :: i
Open( 12 , File = cFilename )
Do i = 1 , size( stStudArray )
Read( 12 , * ) stStudArray( i )%iStuNumber , stStudArray(i)%rScore
End Do
Close( 12 )
End Subroutine GetStudInfo
Subroutine CalcScore( stStud )
Type( T_Stud ) , Intent( INOUT ) :: stStud
Integer :: i
Real :: rTmp
rTmp = 0.0
Do i = 1 , INUMBER_OF_COURSE
rTmp = rTmp + stStud%rScore( i )
End Do
stStud%rScoreAll = rTmp
stStud%rScoreAvg = rTmp / INUMBER_OF_COURSE
End Subroutine CalcScore
Subroutine OutputInfo( stStud , iNum )
Type( T_Stud ) , Intent( IN ) :: stStud(:)
Integer , Intent( IN ) :: iNum
Write(*,"(i,6f7.1,f9.1,f9.3)") stStud( iNum )%iStuNumber,stStud( iNum )%rScore ,stStud( iNum )%rScoreAll, stStud( iNum )%rScoreAvg
End Subroutine OutputInfo
Subroutine HeapSort( stD , comp_f )
Type ( T_Stud ) , Intent( INOUT ) :: stD( : )
Real , External :: comp_f
Integer i,ir,j,l,n
Type ( T_Stud ) :: stTemp
n = size( stD )
If ( n < 2 ) Return
l = n / 2 + 1
ir = n
Do while( .TRUE. )
If( l > 1 ) then
l = l - 1
stTemp = stD( l )
Else
stTemp = stD( ir )
stD( ir ) = stD( 1 )
ir = ir - 1
If( ir == 1 ) then
stD( 1 ) = stTemp
return
End If
End If
i = l
j = l + l
Do while( j<=ir )
If( ( j < ir ) ) then
If ( comp_f( stD(j) , std(j+1) ) > 0.0 ) then
j = j+1
End If
EndIf
If( comp_f( stTemp , stD(j) ) > 0.0 )then
stD(i) = stD( j )
i = j
j = j + j
Else
j = ir + 1
End If
EndDo
stD( i ) = stTemp
End Do
End Subroutine HeapSort
Real Function comp_f_Score( st1 , st2 )
Type( T_Stud ) , Intent( IN ) :: st1 , st2
comp_f_Score = st1%rScoreAll - st2%rScoreAll
End Function comp_f_Score
End Module StudMod
Program Main
Use StudMod
Implicit None
Integer , Parameter :: INUMBER_OF_STUD = 35 !35个学生
Type( T_Stud ) :: stStuds( INUMBER_OF_STUD ) !定义学生数组结构体
Integer :: i , iCourseNumber
Call GetStudInfo( "info.dat" , stStuds ) !读入学生信息
Do i = 1 , INUMBER_OF_STUD
Call CalcScore( stStuds(i) ) !计算平均分和总分
End Do
Call HeapSort( stStuds , comp_f_Score ) !排序
Do i = 1 , INUMBER_OF_STUD
Call OutputInfo( stStuds , i ) !输出排序后的学生信息
End Do
Write(*,*) "请输入挑选的课程号(1-6):"
Read(*,*) iCourseNumber
Do i = 1 , 5
If( stStuds(i)%rScore( iCourseNumber ) > 90.0 ) then
Call OutputInfo( stStuds , i ) !输出满足筛选条件的学生信息
End If
End Do
End Program Main 您好，请参考 彭国伦 教材，第149页。 小新 发表于 2018-5-31 18:48
大哥，不会排序啊
除了说不会以外，会不会学？
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