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| [Fortran] syntaxhighlighter_viewsource syntaxhighlighter_copycode   na = CtreeInd(1, NLayer)
  nb = CtreeInd(2, NLayer)
  do i = na, nb                          !!2547,上面call了,应该是先置零再填充
    a2 = iCtrees(i)%begin                !!begin为起始公共边编号
	b2 = a2 + iCtrees(i)%num - 1         !!节点内公共边的始末编号
	j1 = UnadmInd(1, i)                  !!j1是节点i内近区块的起始编号
	j2 = j1 + UnadmInd(2, i) - 1         !!与i节点相关的不可容块有j2个
	do k = j1, j2                         !!k是近区块的个数,并不是说编号1-56个都在10节点内,而是10节点内有56个近区块
	  j = iUnadms(k)                     !!第k个近区块所在的不可容块为j,是把3104个近区块填充进节点里/近区块关联的编号
	  a1 = iCtrees(j)%begin               !!a1为不可溶块j中包含的起始公共边编号
	  b1 = a1 + iCtrees(j)%num - 1        !!b1为不可溶块j中包含的结尾公共边编号
                                          !!存疑?!但最终是将所有的近区块遍历了一遍
	  allocate( iNears(k)%nr(a1:b1, a2:b2) )
	  call GetZmnMatrix(iNears(k)%nr, iPoints, Npoint, iTris, Ntri, iEdges, Nedge, a1, b1, a2, b2, k0)
	end do
  end do现有一个n*n(6000+*6000+)的方阵,之前的代码已经将矩阵分层,此处iNear(i)代表最小矩阵块,iNear(i)%nr(a1:b1,a2:b2)代表最小矩阵块的边,现在我是把原矩阵重新用簇树结构分层,形式为iblocks(i)%subblocks(j)%nr(a1:b1,a2:b2),现在我做的是将iNear(i)%nr(a1:b1,a2:b2)信息赋给iblocks(i)%subblocks(j)%nr(a1:b1,a2:b2),为啥代码运行一半报错内存溢出?
 有个过渡变量iNear(i)%nr(a1:b1,a2:b2)→iboxNears(i)%nr(a1:b1,a2:b2)→iblocks(i1)%Subblocks(i2)%nr(a1:b1,a2:b2)
 
 求前辈指点一下,我分析不出来..do i = 1, Nunadmdo j = 1, sbmax
 if(untmp(1, i) /= iSubblocks(j)%row) then
 cycle
 else
 if(untmp(2, i) /= iSubblocks(j)%coL) then
 cycle
 else
 j1 = iSubblocks(j)%row
 j2 = iSubblocks(j)%coL
 a2 = iCtrees(j1)%begin
 b2 = a2 + iCtrees(j1)%num - 1
 
 a1 = iCtrees(j2)%begin
 b1 = a1 + iCtrees(j2)%num - 1
 
 i1 = BParam3(j)
 i2 = j - 49*(i1 - k1)
 write(*,*) i1,i2,i,j
 
 allocate(iblocks(i1)%Subblocks(i2)%nrb(a1:b1, a2:b2))
 iblocks(i1)%Subblocks(i2)%nrb = iboxNears(i)%nra
 !             call GetZmnMatrix(iblocks(i1)%iSubblocks(i2)%nr2, iPoints, Npoint, iTris, Ntri, iEdges, Nedge, a1, b1, a2, b2, k0)
 end if
 end if
 end do
 end do
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