trnsys模拟中的fortran的问题，函数调用精度错误？

爱夏无言

trnsys是热力模拟仿真软件，在使用一个部件的时候出现了程序问题，具体哪个部件是 将水与蒸汽混合 其中需要查表来得知一下汽水参数。
运行时出现了以下错误，希望有热力学背景的大神赐教，不惜一切代价

子程序代码如下：

[Fortran] 纯文本查看 复制代码

      SUBROUTINE TYPE304 (TIME,XIN,OUT,T,DTDT,PAR,INFO,ICNTRL,*) 
      USE TrnsysFunctions
        USE TrnsysConstants
      IMPLICIT NONE
        DOUBLE PRECISION XIN,OUT,TIME,PAR,T,DTDT,STORED
      INTEGER*4 INFO(15),NI,NP,NO,ND,NS,IUNIT,ITYPE,ICNTRL
      CHARACTER*3 OCHECK,YCHECK
      PARAMETER (NP=0,NI=7,NO=6,ND=0,NS=0)
      DIMENSION XIN(NI),OUT(NO),PAR(NP),YCHECK(NI),OCHECK(NO),
     & STORED(NS)
        DOUBLE PRECISION FL_Steam, 
     & T_Steam,
     & X_Steam,
     & FL_fw,
     & T_fw,
     & P_out,
     & Tset,
     & P_in,
     & PROP(7),
     & H_steam,
     & Hset,
     & H_fw, 
     & FL_mix,
     & Fl_d_fw,
     & Fl_d_s,
     & Hmix,
     & Tmix,
     & X_mix,
     & IERR,
     & TIME0,
     & DELT,
     & Relax
        PARAMETER ( Relax = 0.05)
        DATA YCHECK/'MF1','TE1','DM1','MF1','TE1','PR1','TE1'/
      DATA OCHECK/'MF1','MF1','MF1','TE1','DM1','PR1'/
      TIME0 = getSimulationStartTime()
      DELT  = getSimulationTimeStep()
      IF(INFO(7).EQ.-2) THEN
          INFO(12)=16
          RETURN 1
        ENDIF
      IF (INFO(8).EQ.-1) THEN
          RETURN 1
        ENDIF
      IF(INFO(13).GT.0) THEN
           RETURN 1
        ENDIF
      IF (INFO(7).EQ.-1) THEN
        IUNIT=INFO(1)
          ITYPE=INFO(2)
          INFO(6)  = NO   
        INFO(9)  = 1  
          INFO(10) = 0   
          CALL setStorageSize(NS,INFO)
          CALL TYPECK(1,INFO,NI,NP,ND)
        CALL RCHECK(INFO,YCHECK,OCHECK)
        RETURN 1
      ENDIF
      IF (TIME.LT.(TIME0+DELT/2.d0)) THEN
        IUNIT=INFO(1)
          ITYPE=INFO(2)
          OUT(1)  = 0.d0                
          OUT(2)  = XIN(1)        
          OUT(3)  = XIN(2)            
          RETURN 1              
      ENDIF
100   CONTINUE
      FL_Steam = XIN(1)
      T_Steam  = XIN(2)
      X_steam  = XIN(3)
      FL_fw    = XIN(4)
      T_fw     = XIN(5)
      P_out    = XIN(6)
      Tset     = XIN(7)
      P_in    = P_out
      IF (x_steam.ge.1 .or. x_steam.le.0) THEN
        PROP(1) = T_Steam
        PROP(2) = 0.1*P_in
        CALL steam3('SI',PROP,12,ierr,*108)
        CALL LINKCK('TYPE 304','Steam  ',1,99)  
108     H_steam = PROP(3) 
      ELSE
        PROP(2) = 0.1*P_in
        PROP(5) = x_Steam
        CALL steam3('SI',PROP,25,ierr,*109)
        CALL LINKCK('TYPE 304','Steam  ',1,99)  
109     H_steam  = PROP(3) 
      ENDIF
      PROP(1) = Tset
      PROP(2) = 0.1*P_out
      CALL steam3('SI',PROP,12,ierr,*110)
      CALL LINKCK('TYPE 304','Steam  ',1,99)  
110   Hset    = PROP(3) 
      PROP(1) = T_fw
      PROP(5) = 0.d0
      CALL steam3('SI',PROP,15,ierr,*112)
      CALL LINKCK('TYPE 304','Steam  ',1,99)  
112   H_fw    = PROP(3) 
      FL_mix  = FL_steam+Fl_fw
        IF ( (Hset-H_fw.LE.0.0).OR.(H_steam-Hset.eq.0.0) ) THEN
        Fl_d_fw = 0.d0
        Fl_d_s  = 0.d0
      ELSE
        Fl_d_fw=
     #  DMIN1(DMAX1(0.,FL_steam * (H_steam-Hset)/(Hset-H_fw)),FL_steam)
        Fl_d_s=DMIN1(DMAX1(0.,Fl_fw * (Hset - H_fw) / 
     #          (H_steam-Hset)),Fl_fw)
      ENDIF
      IF (Fl_mix.le.1e-6) THEN
        Hmix  = H_fw
      ELSE
        Hmix  = (Fl_steam*H_steam + fl_fw*H_fw)/Fl_mix
      ENDIF
      PROP(3) = Hmix
      PROP(2) = 0.1*P_out
      CALL steam_C('SI',PROP,23,ierr,*111)
      CALL LINKCK('TYPE 304','Steam  ',1,99)  
111   Tmix    = PROP(1) 
      x_mix   = DMIN1(2.0,Prop(5))       
200   CONTINUE
        IF (info(7).le.20) THEN
        OUT(1) = FL_d_FW
        OUT(2) = FL_d_S
        OUT(3) = FL_mix
        OUT(4) = Tmix
        OUT(5) = X_mix
        OUT(6) = P_in
        ELSE
        OUT(1) = OUT(1) + relax*(FL_d_FW-out(1))
        OUT(2) = OUT(2) + relax*(FL_d_S-out(2))
        OUT(3) = OUT(3) + relax * (FL_mix -out(3))
        OUT(4) = OUT(4) + relax * (Tmix - out(4))
        OUT(5) = OUT(5) + relax*(X_mix -out(5))
        OUT(6) = P_in        
        ENDIF
      RETURN 1
      END

爱夏无言

其实就是喷水减温的一个部件

爱夏无言

有赐教的大神可以联系我qq342158634，已经困扰我几个月的问题了，解决必有重谢

li913

1、如果你有所有的源代码，检查第一张图上列出的错误行。source为源代码文件名， line 为行号。
2、根据第二张图的提示，应该是混用了单精度和双精度，导致参数传递不对。可能出问题的不是你给出的代码。

爱夏无言

li913 发表于 2018-3-21 10:19
1、如果你有所有的源代码，检查第一张图上列出的错误行。source为源代码文件名， line 为行号。
2、根据第 ...

非常感谢。