Doolittle分解的算法实现问题

1468592801

你在换列的时候是不是写错写成换行了

1468592801

[Fortran] 纯文本查看 复制代码

      module matixsol
      implicit none
      contains
ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
c matrix solving program
c 2024.1.18
c  type|variable | description
c   i  |mata| linear coefficient matrix
c   i  |matb| constant array
c   o  |matx| element array
c the matrixs must be full rank
ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
      subroutine matsolve(mata,matb,matx)
      implicit none
c input/output
      real*8 :: mata(:,:)
      real*8 :: matb(:)
      real*8 :: matx(:)
c temporary variates
      real*8,allocatable :: matl(:,:)
      real*8,allocatable :: matu(:,:)
      real*8,allocatable :: maty(:)
      integer*4 :: numb
      integer*4 :: cycl

ccccccccccccccccccccccccccccccccccc
      numb = size( matb )
      allocate( matl(numb,numb) )
      allocate( matu(numb,numb) )
      allocate( maty(numb) )
c initialize
      matl = 0.0
      matu = 0.0
      maty = 0.0

c LU decomposition of matrix
      matu(1 , 1:numb) = mata(1 , 1:numb)
      matl(1:numb , 1) = mata(1:numb , 1) / matu(1 , 1)
      do cycl = 2 , numb
        matu(cycl , cycl:numb) = mata(cycl , cycl:numb)
     &                         - matmul(matl(cycl , 1:cycl-1)
     &                         , matu(1:cycl-1 , cycl:numb))
        if (cycl .le. numb) then
          matl(cycl:numb , cycl) = (mata(cycl : numb , cycl)
     &                           - matmul(matl(cycl:numb
     &                           , 1:cycl-1) , matu( 1:cycl-1
     &                           , cycl))) / matu(cycl , cycl)
        end if
      end do
c solve Uy=b
      maty(1) = matb(1)
      do cycl = 2 , numb
        maty(cycl) = matb(cycl) - dot_product(matl(cycl , 1:cycl-1)
     &             , maty(1:cycl-1))
      end do

c solve Ux=y
      matx(numb) = maty(numb) / matu(numb , numb)               
      do cycl = numb-1 , 1 , -1
        matx(cycl) = (maty(cycl) - dot_product( matu(cycl , cycl + 1
     &             : numb),matx(cycl + 1 : numb))) / matu(cycl,cycl)
      end do
      return
      end subroutine matsolve
      end module matixsol

这是我之前写的LU的代码，里面也没有换行的操作