出错001,出错002解决

PotsyYZhou · 发表于 2021-11-19 17:03:15

出错001,出错002解决
谢谢
两个程序输出, 如下:
002
Compiled Successfully. Runtime Exceed. Click here to know possible reasons for runtime exceed.
**************************************** 2021-11-19
1                   *** BISECTION METHOD ***
AT ITERATION 1X= 1.500000000AND F(X)=  0.334727906D+00
AT ITERATION 2X= 1.000000000AND F(X)= -0.540302306D+00
AT ITERATION 3X= 1.250000000AND F(X)= -0.921788111D-01
AT ITERATION 4X= 1.375000000AND F(X)=  0.123906023D+00
AT ITERATION 5X= 1.312500000AND F(X)=  0.164999486D-01
AT ITERATION 6X= 1.281250000AND F(X)= -0.376813022D-01
AT ITERATION 7X= 1.296875000AND F(X)= -0.105511125D-01
AT ITERATION 8X= 1.304687500AND F(X)=  0.298432115D-02
AT ITERATION 9X= 1.300781250AND F(X)= -0.378092173D-02
AT ITERATION  10X= 1.302734375AND F(X)= -0.397681601D-03
AT ITERATION  11X= 1.303710938AND F(X)=  0.129347448D-02
AT ITERATION  12X= 1.303222656AND F(X)=  0.447935109D-03
AT ITERATION  13X= 1.302978516AND F(X)=  0.251364218D-04
AT ITERATION  14X= 1.302856445AND F(X)= -0.186270173D-03
AT ITERATION  15X= 1.302917480AND F(X)= -0.805662712D-04
AT ITERATION  16X= 1.302947998AND F(X)= -0.277147736D-04
AT ITERATION  17X= 1.302963257AND F(X)= -0.128913815D-05
AT ITERATION  18X= 1.302970886AND F(X)=  0.119236513D-04
AT ITERATION  19X= 1.302967072AND F(X)=  0.531725892D-05
AT ITERATION  20X= 1.302965164AND F(X)=  0.201406098D-05
AT ITERATION  21X= 1.302964211AND F(X)=  0.362461564D-06
AT ITERATION  22X= 1.302963734AND F(X)= -0.463338254D-06
AT ITERATION  23X= 1.302963972AND F(X)= -0.504383359D-07
AT ITERATION  24X= 1.302964091AND F(X)=  0.156011616D-06
AT ITERATION  25X= 1.302964032AND F(X)=  0.527866408D-07
AT ITERATION  26X= 1.302964002AND F(X)=  0.117415261D-08
AT ITERATION  27X= 1.302963987AND F(X)= -0.246320916D-07
AT ITERATION  28X= 1.302963994AND F(X)= -0.117289695D-07
AT ITERATION  29X= 1.302963998AND F(X)= -0.527740840D-08
AT ITERATION  30X= 1.302964000AND F(X)= -0.205162792D-08
AT ITERATION  31X= 1.302964001AND F(X)= -0.438737657D-09
AT ITERATION  32X= 1.302964001AND F(X)=  0.367707476D-09
AT ITERATION  33X= 1.302964001AND F(X)= -0.355150909D-10
AT ITERATION  34X= 1.302964001AND F(X)=  0.166096192D-09
XTOL MET AT ITERATIONS  34,X= 1.302964001AND F(X)=  0.166096192D-09
            ****MODIFIED LINEAR INTERPOLATION***
AT ITERATION 1X= 2.500000000AND F(X)=  0.171743435D+01
AT ITERATION 2X= 2.500000000AND F(X)=  0.171743435D+01
AT ITERATION 3X= 2.500000000AND F(X)=  0.171743435D+01
AT ITERATION 4X= 2.500000000AND F(X)=  0.171743435D+01
AT ITERATION 5X= 2.500000000AND F(X)=  0.171743435D+01
AT ITERATION 6X= 2.500000000AND F(X)=  0.171743435D+01
***********************

***********************
001:
Compiled Successfully. memory: 2980 time: 0.02 exit code: 2
--------------------------------
  COEFFICIENT OF THE MATRIX
--------------------------------
         9.37460 3.04160  -2.43710
         3.04160 6.18320 1.21630
         -2.43710 1.21630 8.44290
      SOLUTIONS WITH DIFFERENT RHS :
         4.00000 3.00000 2.00000
         4.00000 2.00000 1.00000
         1.00000  -1.00000 4.00000
      LU DECOMPOSITION OF THE MATRIX
         9.37460 0.32445  -0.25997 0.31253 0.22214 0.43156
         3.04160 5.19635 0.38624 0.46532 0.23143  -0.17317
         -2.43710 2.00702 7.03415 0.14162  -0.08766 0.62329
      DETERMENANT OF THE MATRIX:
         342.659
         INVERSE OF THE MATRIX :
         0.14803  -0.08359 0.05477
         -0.08359 0.21365  -0.05491
         0.05477  -0.05491 0.14216
***********************
比较结果, 效果良好! 顺利! 再见! 羊城
2021-11-19

[求助] 出错001,出错002解决